本文共 3347 字,大约阅读时间需要 11 分钟。
迭代法实现字符串反转
public String reserve(String originString){ if(originString==null||originString.length()==1){ return originString; } return reserve(originString.substring(1))+originString.charAt(0); }判断字符串是否包含重复字符
public static boolean containRepeatChar(String str){ if(str==null||str.isEmpty()){ return false; } char[] elements=str.toCharArray(); for(char e:elements){ if(str.indexOf(e)!=str.lastIndexOf(e)){ return true; } } return false; }
多组输入十六进制转化十进制
public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); while(sc.hasNext()){ String input = sc.nextLine(); int sum = convert(input); System.out.println(sum); } } public static int convert(String str){ if(str==null||str.length()==0){ return 0; } int sum = 0; int temp = 0; int n = 16;//进制数 char ch; String input = str.substring(2,str.length()); int count = input.length()-1; for(int i=0;i连续输入字符串,请按长度为8拆分每个字符串后输出到新的字符串数组;长度不是8整数倍的字符串请在后面补数字0,空字符串不处理。='0'&&ch<='9'){ temp = ch - '0'; } else if(ch>='a'&&ch<='z'){ temp = ch - 'a' + 10; } else if(ch>='A'&&ch<='Z'){ temp = ch -'A' + 10; }else{ break; } sum += temp*Math.pow(n,count); count--; } return sum; }}
public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); while(sc.hasNext()){ String s = new String(sc.nextLine()); if(s.length()%8 !=0 ) s = s + "00000000"; while(s.length()>=8){ System.out.println(s.substring(0, 8)); s = s.substring(8); } } } }
删除字符串中出现次数最少的字符
import java.util.Collection;import java.util.Collections;import java.util.LinkedHashMap;import java.util.Map;import java.util.Scanner;public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); while(in.hasNext()) { String inputString = in.next(); char[] inputChar = inputString.toCharArray(); Mapmap = new LinkedHashMap<>(); for (char c : inputChar) { if(map.containsKey(c)) { map.put(c, map.get(c)+1); }else { map.put(c, 1); } } Collection values = map.values();//工具类要常用! int minIndex = Collections.min(values);//直接借助collections找最值! StringBuffer sb = new StringBuffer(); for (char keys : inputChar) { if(map.get(keys) != minIndex) { sb.append(keys); } } System.out.println(sb); } }}
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